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Friday, October 26, 2012

Sex math is hard

I promise maybe this is the last post about sex week, but the articles are just so great. So, this problem could be posed in the simplest of terms: when there are fewer lesbians than straight women, it's harder to find lesbians in any given population of women. Check. But it could also be posed in this amazing baroque way as the world's greatest math problem:
As a pansexual, Jinadasa expresses a desire to have relationships with both men and women, but she says that the small dating pool of lesbian and female bisexuals makes it much easier to date men. “It’s math: Let’s say I’m attracted to 50 percent women and 50 percent men. Let’s say there are 40 people in a room and I’m attracted to all of the guys and all of the girls. There are nine guys who are gay and one girl who is queer.”
Ok, peeps, let's put our thinking caps on. So there are 40 people in a room, and you are attracted to all of them, every last one, but you're still a woman, so the nine gay guys are not attracted to you (annoying! why can't they also be pansexual?), which leaves 31 people to potentially sleep with. It could work out with one of the girls, but that seems so...paltry. You are hot stuff, you desire everyone, can't a girl get some play? What about the other 30 people? Are they men or women? Now your calculator is giving you "variable undefined" as an answer. Maybe they are also pansexuals, so it's irrelevant? Or maybe they are all having sex with each other while you're busy doing this math, and by the time you finish and go back into the room, you'll discover that they all got tired and left, including that one queer girl you could've met instead of doing this complicated sex-algebra? Then, you'll realize that all you needed to satisfy your vast pan-desire was one person, queer or not, and in spite of being attracted to 40 people simultaneously, you're still stuck going home alone.

If only this epic story could one day appear as a word problem in the math textbooks of future children.

4 comments:

Sigivald said...

... so how is "pansexual" different from "bisexual", in that definition?

I'd been under the impression it was supposed to be different somehow.

Anyway -

Assume a 50/50 gender split in that 40 people (which is fair if she is both not specifying and complaining not that there are not enough women, but not enough gay women), and she's reporting that 45% of men she meets are gay, but "only" 5% of women are?

I think the real problem for her is her social group, since as far as I understand the data, something just under 5% of both genders are gay in the general population.

So she seems to be right on average for gay women in her sample, and vastly over-representing gay men.

Where are all the extra homosexual men in her sample coming from? And if she doesn't like it, why doesn't she change it?

Find more straight men or gay women!

Miss Self-Important said...

Yes, so this math problem is very complex indeed, because students may also need to account for how the room was peopled in the first place.

It's not clear what the difference is in this description except that the room hypothetical suggests an especially active libido is attached to pansexuality. Wikipedia does not corroborate this suggestion, however. Pansexuality rejects the gender binary assumed by bisexuality, thereby including various trans- and non-gendered persons within its, err, fold. So it's a more PC version of bisexuality, which is downright old-fashioned in these times?

FLG said...

I don't understand what the problem is. There's a book called ‘Finding the Lesbians.’ Problem solved.

Miss Self-Important said...

But this woman does not evidently own the book or know the woman who does in order to borrow it because she can't find her in order to meet her.